AQA GCSE Physics contents

Unit 1 · Energy

Efficiency & Energy Resources

3 min read · part of the full Exam Guide

Efficiency

  • Recall both equations:
efficiency=useful output energy transfertotal input energy transferefficiency=useful power outputtotal power input \text{efficiency} = \frac{\text{useful output energy transfer}}{\text{total input energy transfer}} \qquad \text{efficiency} = \frac{\text{useful power output}}{\text{total power input}}
  • Efficiency has no unit. It is a decimal between 0 and 1, or a percentage (multiply by 100). It can never be more than 1 (100%)
  • Worked example: a motor takes in 500 J and does 350 J of useful work. Efficiency =350500=0.7=70%= \dfrac{350}{500} = 0.7 = 70\%. The other 150 J is dissipated to the thermal store
  • Rearranged: useful output == efficiency ×\times input
  • (HT) To increase the efficiency of an intended transfer: lubricate moving parts, insulate against heating losses, streamline to reduce air resistance, use low-resistance wires to reduce heating in circuits, and recover wasted energy (a heat exchanger)

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Sankey diagram — a filament lamp100 Jelectrical energy in10 J — useful LIGHT90 J — wasted, dissipated to thesurroundings by heatingthe width of each arrow is proportional to the energy it carriesefficiency = useful energy out ÷ total energy in × 100 = 10 ÷ 100 × 100 = 10%The energy is not destroyed — it is dissipated to the surroundings, where it is spread out sothinly that it can no longer do anything useful. An LED lamp is far more efficient, which is whyfilament lamps have been phased out.
A Sankey diagram for a filament lamp: 100 J in, a thin arrow of 10 J useful light out and a thick arrow of 90 J dissipated by heating

Full Exam Guide

The rest of this topic is in the full Exam Guide

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In the full topic

  • Efficiency
  • Energy resources
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